Wiman's type inequality for analytic and entire functions and h-measure of an exceptional sets

Keywords:
Wiman's inequality, analytic function, maximum modulus, maximal term, exceptional set, h-measureAbstract
Let ER be the class of analytic functions f represented by power series of the form f(z)=+∞∑n=0anzn with the radius of convergence R:=R(f)∈(0;+∞]. For r∈[0,R) we denote the maximum modulus by Mf(r)=max{|f(z)|: |z|=r} and the maximal term of the series by μf(r)=max{|an|rn:n≥0}. We also denote by HR, R≤+∞, the class of continuous positive functions, which increase on [0;R) to +∞, such that h(r)≥2 for all r∈(0,R) and ∫Rr0h(r)dlnr=+∞ for some r0∈(0,R). In particular, the following statements are proved.
10. If h∈HR and f∈ER, then for any δ>0 there exist E(δ,f,h):=E⊂(0,R), r0∈(0,R) such that ∀ r∈(r0,R)∖E: Mf(r)≤h(r)μf(r){lnh(r)ln(h(r)μf(r))}1/2+δ and ∫Eh(r)dlnr<+∞.
20. If we additionally assume that the function f∈ER is unbounded, then lnMf(r)≤(1+o(1))ln(h(r)μf(r)) holds as r→R, r∉E.
Remark, that assertion 10 at h(r)≡const implies the classical Wiman-Valiron theorem for entire functions and at h(r)≡1/(1−r) theorem about the Kövari-type inequality for analytic functions in the unit disc. From statement 20 in the case that lnh(r)=o(lnμf(r)), r→R, it follows that lnMf(r)=(1+o(1))lnμf(r) holds as r→R, r∉E.